1100=m^2

Solution for 1100=m^2 equation:

1100=m^2

We move all terms to the left:

1100-(m^2)=0

We add all the numbers together, and all the variables

-1m^2+1100=0

a = -1; b = 0; c = +1100;
Δ = b2-4ac
Δ = 02-4·(-1)·1100
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{11}}{2*-1}=\frac{0-20\sqrt{11}}{-2}
=-\frac{20\sqrt{11}}{-2}
=-\frac{10\sqrt{11}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{11}}{2*-1}=\frac{0+20\sqrt{11}}{-2}
=\frac{20\sqrt{11}}{-2}
=\frac{10\sqrt{11}}{-1}
$